RS Aggarwal Class 9 Math Chapter 2 Polynomials Exercise 2F Solution

EXERCISE 2F

Question 1:
25x2 – 64y2
= (5x)2 – (8y)2
= (5x + 8y) (5x – 8y)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 1.1

Question 2:
100 – 9x2
= (10)2 – (3x)2
= (10 + 3x) (10 – 3x)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 2.1

Question 3:
5x2 – 7y2
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 3.1

Question 4:
(3x + 5y)2 – 4z2
= (3x + 5y)2 – (2z)2
= (3x + 5y + 2z) (3x + 5y – 2z)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 4.1

Question 5:
150 – 6x2
= 6 (25 – x2)
= 6 (52 – x2)
= 6 (5 + x) (5 – x)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 5.1

Question 6:
20x2 – 45
= 5(4x2 – 9)
= 5 [(2x)2 – (3)2]
= 5 (2x + 3) (2x – 3)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 6.1

Question 7:
3x3 – 48x
= 3x (x2 – 16)
= 3x [(x)2 – (4)2]
= 3x (x + 4) (x – 4)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 7.1

Question 8:
2 – 50x2
= 2 (1 – 25x2)
= 2 [(1)2 – (5x)2]
= 2 (1 + 5x) (1 – 5x)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 8.1

Question 9:
27a2 – 48b2
= 3 (9a2 – 16b2)
= 3 [(3a)2 – (4b)2]
= 3(3a + 4b) (3a – 4b)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 9.1

Question 10:
x – 64x3
= x (1 – 64x2)
= x[(1)2 – (8x)2]
= x (1 + 8x) (1 – 8x)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 10.1

Question 11:
8ab2 – 18a3
= 2a (4b2 – 9a2)
= 2a [(2b)2 – (3a)2]
= 2a (2b + 3a) (2b – 3a)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 24.2

Question 12:
3a3b – 243ab3
= 3ab (a2 – 81 b2)
= 3ab [(a)2 – (9b)2]
= 3ab (a + 9b) (a – 9b)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 24.2

Question 13:
(a + b)3 – a – b
= (a + b)3 – (a + b)
= (a + b) [(a + b)2 – 12]
= (a + b) (a + b + 1) (a + b – 1)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 11.1

Question 14:
108a2 – 3(b – c)2
= 3 [(36a2 – (b -c)2]
= 3 [(6a)2 – (b – c)2]
= 3 (6a + b – c) (6a – b + c)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 12.1

Question 15:
x3 – 5x2 – x + 5
= x2 (x – 5) – 1 (x – 5)
= (x – 5) (x2 – 1)
= (x – 5) (x + 1) (x – 1)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 13.1

Question 16:
a2 + 2ab + b2 – 9c2
= (a + b)2 – (3c)2
= (a + b + 3c) (a + b – 3c)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 14.1

Question 17:
9 – a2 + 2ab – b2
= 9 – (a2 – 2ab + b2)
= 32 – (a – b)2
= (3 + a – b) (3 – a + b)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 15.1

Question 18:
a2 – 4ac + 4c2 – b2
= a2 – 4ac + 4c2 – b2
= a2 – 2 a 2c + (2c)2 – b2
= (a – 2c)2 – b2
= (a – 2c + b) (a – 2c – b)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 16.1

Question 19:
9a2 + 3a – 8b – 64b2
= 9a2 – 64b2 + 3a – 8b
= (3a)2 – (8b)2 + (3a – 8b)
= (3a + 8b) (3a – 8b) + (3a – 8b)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 17.1
= (3a – 8b) (3a + 8b + 1)

Question 20:
x2 – y2 + 6y – 9
= x2 – (y2 – 6y + 9)
= x2 – (y2 – 2 y 3 + 32)
= x2 – (y – 3)2
= [x + (y – 3)] [x – (y – 3)]
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 18.1
= (x + y – 3) (x – y + 3)

Question 21:
4x2 – 9y2 – 2x – 3y
= (2x)2 – (3y)2 – (2x + 3y)
= (2x + 3y) (2x – 3y) – (2x + 3y)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 19.1
= (2x + 3y) (2x – 3y – 1)

Question 22:
x4 – 1
= (x2 )2 – 12
= (x2 + 1) (x2 – 1) RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 21.1
= (x2 + 1) (x + 1) (x – 1)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 20.1

Question 23:
a – b – a2 + b2
= (a – b) – (a2 – b2)
= (a – b) – (a – b) (a + b)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 22.1
= (a – b) (1 – a – b)

Question 24:
x4 – 625
= (x2)2 – (25)2
= (x2 + 25) (x2 – 25)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 23.1
= (x2 + 25) (x2 – 52)
= (x2 + 25) (x + 5) (x – 5)
RS Aggarwal Solutions Class 9 Chapter 2 Polynomials 2f 24.1