RS Aggarwal Solutions Class 9 Chapter 14 Statistics Solution
EXERCISE 14H
Question 1:
Arrange the given data in ascending order we have
0, 0, 1, 2, 3, 4, 5, 5, 6, 6, 6, 6
Let us prepare the following table:
Observations(x) |
0 | 1 | 2 | 3 | 4 | 5 | 6 |
Frequency | 2 | 1 | 1 | 1 | 1 | 2 |
4 |
As 6 ocurs the maximum number of times i.e. 4, mode = 6
Question 2:
Arranging the given data in ascending order , we have:
15, 20, 22, 23, 25, 25, 25, 27, 40
The frequency table of the data is :
Observations(x) |
15 | 20 | 22 | 23 | 25 | 27 | 40 |
Frequency | 1 | 1 | 1 | 1 | 3 | 1 |
1 |
As 25 ocurs the maximum number of times i.e. 3, mode = 25
Question 3:
Arranging the given data in ascending order , we have:
1, 1, 2, 3, 3, 4, 5, 5, 6, 6, 7, 8, 9, 9, 9, 9, 9,
The frequency table of the data is :
Observations(x) |
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
Frequency |
2 | 1 | 2 | 1 | 2 | 2 | 1 | 1 | 5 |
As 9, occurs the maximum number of times i.e. 5, mode = 9
Question 4:
Arranging the given data in ascending order , we have:
9, 19, 27, 28, 30, 32, 35, 50, 50, 50, 50, 60
The frequency table of the data is :
Observations(x) |
9 | 19 | 27 | 28 | 30 | 32 | 35 | 50 | 60 |
Frequency | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 4 |
1 |
As 50, ocurs the maximum number of times i.e. 4, mode = 50
Thus, the modal score of the cricket player is 50.
Question 5:
Arranging the given data in ascending order , we have:
10, 10, 11, 11, 12, 12, 13, 14, 15, 17
We may prepare the table, given below:
Item(x) |
Frequency(f) | Cumulative Frequency | f x |
10
11 12 13 14 15 17 |
2
2 2 1 1 1 1 |
2
4 6 7 8 9 10 |
20 22 24 13 14 15 17 |
N=10 |
\(\sum { f\times x } =125 \) |
Question 6:
Question 7:
Question 8:
Question 9:
Question 10:
Question 11:
Question 12: